The product rule states (fg)′=f′g+fg′ and the quotient rule states (gf)′=g2f′g−fg′. Both are essential because derivatives of products and quotients cannot be found by simply differentiating each piece separately.
Product and Quotient Rules
When differentiating a product or quotient of functions, you cannot simply differentiate each piece separately. Instead, use these two fundamental rules.
The Rules
If h(x)=f(x)g(x), then the product rule is:
h′(x)=f′(x)g(x)+f(x)g′(x)
If h(x)=g(x)f(x), then the quotient rule is:
h′(x)=[g(x)]2f′(x)g(x)−f(x)g′(x)
Why These Rules Matter
The intuitive guess that (fg)′=f′g′ fails. For example, if f(x)=x and g(x)=x, then fg=x2 so (fg)′=2x, but f′g′=1⋅1=1. The product rule exists because both functions change simultaneously—the rate of change of a product depends on how each piece contributes to the overall change.
Worked Examples
Product Rule: Differentiate h(x)=x2sinx.
Let f(x)=x2 and g(x)=sinx, so f′(x)=2x and g′(x)=cosx.
h′(x)=2xsinx+x2cosx
Quotient Rule: Differentiate h(x)=sinxx2.
Using the same f and g:
h′(x)=sin2x2xsinx−x2cosx
Note the order and minus sign—these are critical differences from the product rule.
Common Pitfall
A helpful mnemonic for the quotient rule is "low d-high minus high d-low, over low squared," where "low" is the denominator and "high" is the numerator. This prevents accidentally reversing the subtraction, which would flip your answer's sign.
Combining Rules
When pieces are composite functions, combine the product or quotient rule with the chain rule. For x2e3x: apply the product rule where f′=2x and g′=3e3x (using the chain rule on the exponential), yielding h′(x)=2xe3x+3x2e3x.
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