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Limit Laws

Limit laws let you evaluate complex limits by breaking them into simpler pieces, finding each limit, then combining using algebraic rules for sums, differences, products, quotients, and powers—provided denominators don't approach zero.

Limit Laws: Combining Simple Limits

Limit laws are algebraic rules that let you evaluate limits of complicated expressions by breaking them into simpler pieces. If lim⁡x→af(x)=L\lim_{x\to a} f(x) = L and lim⁡x→ag(x)=M\lim_{x\to a} g(x) = M both exist, you can combine these limits using predictable rules—without graphing or building tables.

Core Rules

The sum, difference, and product rules work intuitively:

lim⁡x→a[f(x)+g(x)]=L+Mlim⁡x→a[f(x)−g(x)]=L−Mlim⁡x→a[f(x)⋅g(x)]=L⋅M\lim_{x\to a}[f(x)+g(x)] = L+M \quad \lim_{x\to a}[f(x)-g(x)] = L-M \quad \lim_{x\to a}[f(x)\cdot g(x)] = L\cdot M

A special case is the constant multiple rule: lim⁡x→ac f(x)=c L\lim_{x\to a} c\,f(x) = c\,L.

The quotient rule requires one critical condition:

lim⁡x→af(x)g(x)=LMprovided M≠0\lim_{x\to a} \frac{f(x)}{g(x)} = \frac{L}{M} \quad \text{provided } M \neq 0

For powers and roots:

lim⁡x→a[f(x)]n=Lnlim⁡x→af(x)n=Ln\lim_{x\to a} [f(x)]^n = L^n \quad \lim_{x\to a} \sqrt[n]{f(x)} = \sqrt[n]{L}

Direct Substitution

These laws justify direct substitution: for polynomials, rational functions (where the denominator isn't zero), and root functions at domain points, simply plug in the value. For example, lim⁡x→23x2−5x+1=3(4)−53=73\lim_{x\to 2}\frac{3x^2-5}{x+1} = \frac{3(4)-5}{3} = \frac{7}{3}.

When Limit Laws Break Down

The quotient rule fails when M=0M = 0. Division by zero creates an indeterminate form (0/00/0) or undefined expression. When this occurs, you need algebraic techniques like factoring or rationalizing to resolve the limit—the rule simply doesn't apply.

Example

Evaluate lim⁡x→12x3+4x+3\lim_{x\to 1}\sqrt{\frac{2x^3+4}{x+3}}:

lim⁡x→1(2x3+4)=6,lim⁡x→1(x+3)=4  (≠0)\lim_{x\to 1}(2x^3+4) = 6, \quad \lim_{x\to 1}(x+3) = 4 \;(\neq 0)

⇒lim⁡x→12x3+4x+3=64=32⇒lim⁡x→12x3+4x+3=32\Rightarrow \lim_{x\to 1}\frac{2x^3+4}{x+3} = \frac{6}{4} = \frac{3}{2} \quad \Rightarrow \quad \lim_{x\to 1}\sqrt{\frac{2x^3+4}{x+3}} = \sqrt{\frac{3}{2}}

Recognizing when limit laws apply—and when they fail—is as important as knowing the laws themselves.

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