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Applying the sum and power rules for limits

Suppose lim⁡x→af(x)=1\lim_{x \to a} f(x) = 1 and lim⁡x→ag(x)=3\lim_{x \to a} g(x) = 3. Let r(x)=[f(x)+g(x)]3r(x) = [f(x) + g(x)]^3.

Using the limit laws, find lim⁡x→ar(x)\lim_{x \to a} r(x).

Hint

First apply the sum rule to find lim⁡x→a[f(x)+g(x)]\lim_{x \to a} [f(x) + g(x)], then apply the power rule to raise that result to the third power.

Step-by-step solution

By the sum rule for limits, lim⁡x→a[f(x)+g(x)]=lim⁡x→af(x)+lim⁡x→ag(x)=1+3=4\lim_{x \to a} [f(x) + g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x) = 1 + 3 = 4.

Now apply the power rule, which states lim⁡x→a[h(x)]n=[lim⁡x→ah(x)]n\lim_{x \to a} [h(x)]^n = \left[\lim_{x \to a} h(x)\right]^n for a positive integer nn. Here h(x)=f(x)+g(x)h(x) = f(x)+g(x) and n=3n=3, so lim⁡x→ar(x)=43=64\lim_{x \to a} r(x) = 4^3 = 64.

Identifying the order of limit law application

Hint
Step-by-step solution

The sum rule is applied first. In part a, the sum rule was used to combine the limits of f of x and g of x into a single value, four, before that result was raised to the third power using the power rule. Applying the power rule first would not make sense, since the exponent applies to the sum of the functions, not to each function separately.

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