← Back to learning objective

Limit of a product involving a power rule

Suppose lim⁡x→af(x)=9\lim_{x \to a} f(x) = 9 and lim⁡x→ag(x)=5\lim_{x \to a} g(x) = 5.

Let z(x)=[f(x)]1/2⋅g(x)z(x) = [f(x)]^{1/2} \cdot g(x). Using the limit laws, find lim⁡x→az(x).\lim_{x \to a} z(x).

Hint

Apply the power rule to find lim⁡x→a[f(x)]1/2\lim_{x\to a}[f(x)]^{1/2} first, then use the product rule to combine it with lim⁡x→ag(x)\lim_{x\to a} g(x).

Step-by-step solution

Since lim⁡x→af(x)=9\lim_{x\to a} f(x) = 9, the power rule gives lim⁡x→a[f(x)]1/2=(lim⁡x→af(x))1/2=91/2=3\lim_{x\to a} [f(x)]^{1/2} = \left(\lim_{x\to a} f(x)\right)^{1/2} = 9^{1/2} = 3.

Now apply the product rule: lim⁡x→az(x)=lim⁡x→a[f(x)]1/2⋅lim⁡x→ag(x)=3⋅5=15\lim_{x\to a} z(x) = \lim_{x\to a} [f(x)]^{1/2} \cdot \lim_{x\to a} g(x) = 3 \cdot 5 = 15.

Related problems

Practice similar Calculus problems interactively.

Start Closing the Gap