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Derivative of f(x) = x via the power rule

Consider the simple linear function f(x)=xf(x) = x.

Let f(x)=xf(x) = x. Use the power rule to find f′(x)f'(x), and then explain what this derivative value tells you about the slope of the graph of ff at every point xx.

Hint

Rewrite xx as x1x^1 and apply the power rule ddx[xn]=nxn−1\frac{d}{dx}[x^n] = n x^{n-1}. Then think about what a constant derivative means geometrically.

Step-by-step solution

Write f(x)=x=x1f(x) = x = x^1. By the power rule, ddx[xn]=nxn−1\frac{d}{dx}[x^n] = n x^{n-1}, so with n=1n=1 we get f′(x)=1⋅x1−1=1⋅x0=1⋅1=1f'(x) = 1\cdot x^{1-1} = 1\cdot x^0 = 1\cdot 1 = 1.

Since f′(x)=1f'(x) = 1 for every value of xx, the slope of the tangent line to f(x)=xf(x) = x is the same, namely 11, at every point on the graph. This makes sense because f(x)=xf(x)=x is itself a straight line with slope 11, so its tangent line at any point coincides with the line itself.

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