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Derivative of a negative fractional power

Let f(x)=x−2/3f(x) = x^{-2/3}. Find f′(x)f'(x).

Hint

Apply the power rule ddx[xn]=nxn−1\frac{d}{dx}[x^n] = n x^{n-1} directly using n=−23n = -\frac{2}{3}, then simplify the resulting exponent by subtracting 1 from it carefully.

Step-by-step solution

Using the power rule with n=−23n = -\frac{2}{3}, we get f′(x)=−23x−2/3−1f'(x) = -\frac{2}{3} x^{-2/3 - 1}. Subtracting 1 from the exponent requires writing 1=331 = \frac{3}{3}, so −23−33=−53-\frac{2}{3} - \frac{3}{3} = -\frac{5}{3}.

Therefore f′(x)=−23x−5/3f'(x) = -\frac{2}{3} x^{-5/3}. This can also be written as f′(x)=−23x5/3f'(x) = -\dfrac{2}{3x^{5/3}}, since a negative exponent indicates a reciprocal.

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