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Chain rule with a sine composite function

Let g(x)=sin⁡(5x2+1)g(x) = \sin(5x^2 + 1). Find g′(x)g'(x).

Hint

Identify the outer function f(u)=sin⁡(u)f(u) = \sin(u) and the inner function u=g(x)=5x2+1u = g(x) = 5x^2+1. Differentiate the outer function with respect to uu, differentiate the inner function with respect to xx, then multiply the two results together according to the chain rule.

Step-by-step solution

Write the function as a composition f(u)=sin⁡(u)f(u) = \sin(u) where u=5x2+1u = 5x^2 + 1. The derivative of the outer function is f′(u)=cos⁡(u)f'(u) = \cos(u), and the derivative of the inner function is u′=ddx[5x2+1]=10xu' = \dfrac{d}{dx}[5x^2+1] = 10x.

By the chain rule, g′(x)=f′(u)⋅u′=cos⁡(5x2+1)⋅10xg'(x) = f'(u)\cdot u' = \cos(5x^2+1)\cdot 10x. Rearranging gives the final answer g′(x)=10xcos⁡(5x2+1)g'(x) = 10x\cos(5x^2+1).

Identifying the outer function in the sine composite

Hint
Step-by-step solution

The outer function was f of u equals sine of u. This is the function applied last, wrapping around the inner expression five x squared plus one. Recognizing this split is what allows the chain rule to be applied correctly.

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