← Back to learning objective

Chain rule with a polynomial inner function

Let f(x)=(3x2−5x+1)4f(x) = (3x^2 - 5x + 1)^4. Find f′(x)f'(x).

Hint

Think of f(x)f(x) as u4u^4 where u=3x2−5x+1u = 3x^2 - 5x + 1. Apply the chain rule: differentiate the outer power function first, then multiply by the derivative of the inner function uu.

Step-by-step solution

Identify the outer function as f(u)=u4f(u) = u^4 and the inner function as u=g(x)=3x2−5x+1u = g(x) = 3x^2 - 5x + 1. By the chain rule, ddx[f(g(x))]=f′(g(x))⋅g′(x)\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x), where f′(u)=4u3f'(u) = 4u^3.

Compute the derivative of the inner function: g′(x)=6x−5g'(x) = 6x - 5. Substituting back gives f′(x)=4(3x2−5x+1)3⋅(6x−5)f'(x) = 4(3x^2 - 5x + 1)^3 \cdot (6x - 5), which is the final simplified derivative.

Related problems

Practice similar Calculus problems interactively.

Start Closing the Gap