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Implicit Differentiation

Implicit differentiation finds dydx\frac{dy}{dx} for equations mixing xx and yy without solving for yy explicitly. Differentiate both sides with respect to xx, apply the chain rule to yy-terms (multiplying by dydx\frac{dy}{dx}), use the product rule for xyxy terms, then solve for dydx\frac{dy}{dx}.

What Is Implicit Differentiation?

Many equations mix xx and yy in ways that make isolating yy difficult or impossible—like x2+y2=25x^2 + y^2 = 25 or y3+xy=7y^3 + xy = 7. Implicit differentiation lets you find dydx\frac{dy}{dx} directly without rearranging. The core idea: treat yy as a function of xx and differentiate both sides of the equation, applying the chain rule to every yy-term.

The Key Rule

Since yy is secretly a function of xx, when you differentiate any power of yy, the chain rule requires an extra factor:

ddx[yn]=nyn−1⋅dydx\frac{d}{dx}\left[y^n\right] = ny^{n-1}\cdot\frac{dy}{dx}

This dydx\frac{dy}{dx} factor appears every time—forgetting it is the most common mistake.

The Four-Step Procedure

  1. Differentiate both sides with respect to xx. Apply the chain rule to all yy-terms and the product/quotient rule wherever xx and yy multiply or divide.
  2. Expand any products.
  3. Collect all dydx\frac{dy}{dx} terms on one side; move everything else to the other.
  4. Factor and solve for dydx\frac{dy}{dx}.

Simple Example: The Circle

For x2+y2=25x^2 + y^2 = 25:

2x+2ydydx=02x + 2y\frac{dy}{dx} = 0

dydx=−xy\frac{dy}{dx} = -\frac{x}{y}

Notice the answer depends on both xx and yy—this is normal. Geometrically, −x/y-x/y is the slope of the tangent line at any point on the circle.

Graph illustrating Implicit Differentiation

Watch Out for Products

When xx and yy multiply, use the product rule first, then attach dydx\frac{dy}{dx} to the yy derivative:

ddx[xy]=y+xdydx\frac{d}{dx}[xy] = y + x\frac{dy}{dx}

Missing the dydx\frac{dy}{dx} on the second term is a frequent error. Always ask: "Is this a product of an xx-part and a yy-part?" If yes, product rule applies.

Practice problems

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