← Back to learning objective

Implicit differentiation to find dy/dx at a point

The equation x2+y2=25x^2 + y^2 = 25 defines a circle of radius 5, and it implicitly defines yy as a function of xx near the point (3,4)(3,4).

Given the equation x2+y2=25,x^2 + y^2 = 25, use implicit differentiation to find dydx\frac{dy}{dx}, and then evaluate it at the point (3,4)(3,4).

Hint

Differentiate both sides with respect to xx, remembering that yy is a function of xx, so ddx[y2]=2ydydx\frac{d}{dx}[y^2] = 2y\frac{dy}{dx} by the chain rule. Then solve for dydx\frac{dy}{dx} and substitute x=3x=3, y=4y=4.

Step-by-step solution

Differentiate both sides of x2+y2=25x^2 + y^2 = 25 with respect to xx. The left side gives 2x+2ydydx2x + 2y\frac{dy}{dx} (using the chain rule on y2y^2), and the right side, being constant, gives 00. This yields 2x+2ydydx=02x + 2y\frac{dy}{dx} = 0.

Solve for dydx\frac{dy}{dx}: subtract 2x2x from both sides and divide by 2y2y to get dydx=−xy\frac{dy}{dx} = -\frac{x}{y}. Substituting x=3x=3 and y=4y=4 gives dydx=−34\frac{dy}{dx} = -\frac{3}{4}.

Sign of the slope on the circle

Hint
Step-by-step solution

The derivative formula found earlier is negative x over y. At the point negative three, four, substituting gives negative negative three over four, which simplifies to positive three fourths. So the slope at this point is positive.

Related problems

Practice similar Calculus problems interactively.

Start Closing the Gap