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Existence Of Limits

A limit lim⁡x→af(x)\lim_{x \to a} f(x) exists if and only if both one-sided limits exist and equal the same finite value. Limits fail when one-sided limits disagree, the function grows unbounded, or oscillates without settling.

When Does a Limit Fail to Exist?

A limit lim⁡x→af(x)=L\lim_{x \to a} f(x) = L exists when f(x)f(x) approaches a single, finite value LL from both sides as xx approaches aa. When this doesn't happen, we say the limit does not exist (DNE).

The Core Requirement

A two-sided limit exists if and only if both one-sided limits exist and are equal: lim⁡x→a−f(x)=lim⁡x→a+f(x)=L\lim_{x\to a^-} f(x) = \lim_{x\to a^+} f(x) = L

If the left-hand and right-hand limits differ, there is no single value the function approaches — the limit fails.

Three Ways Limits Fail to Exist

1. Disagreeing One-Sided Limits

When left and right limits approach different values, the limit does not exist. For example: f(x)={x+1x<24−xx≥2f(x) = \begin{cases} x+1 & x < 2 \\ 4-x & x \ge 2\end{cases}

As x→2−x \to 2^-, f(x)→3f(x) \to 3; as x→2+x \to 2^+, f(x)→2f(x) \to 2. Since 3≠23 \ne 2, the limit at x=2x=2 does not exist.

Graph illustrating Existence Of Limits

2. Unbounded Growth

If f(x)f(x) grows without bound (toward ±∞\pm\infty) as x→ax \to a, no finite limit exists. This creates a vertical asymptote.

3. Oscillation

The function may stay bounded but oscillate without settling. Consider f(x)=sin⁡(1/x)f(x) = \sin(1/x) as x→0x \to 0: the argument 1/x1/x grows huge, causing sin⁡(1/x)\sin(1/x) to cycle repeatedly between −1-1 and 11 infinitely often. The function never approaches a single value, so the limit does not exist.

Graph illustrating Existence Of Limits (2)

Key Insight

Remember: a limit exists only when f(x)f(x) approaches one specific, finite number consistently from both sides. The function's value at aa itself (f(a)f(a)) is irrelevant — only the behavior near aa matters. Disagreement between sides, unbounded growth, or endless oscillation all signal that the limit fails.

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