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Differentiability

A function is differentiable at a point if its derivative exists as a finite number—geometrically, the curve has a well-defined non-vertical tangent. Differentiability fails at corners (mismatched slopes), cusps (opposite infinities), and vertical tangents (same infinity both sides), even when the function is continuous.

Understanding Differentiability

A function ff is differentiable at x=ax=a if the derivative f′(a)=lim⁡h→0f(a+h)−f(a)hf'(a) = \lim_{h\to 0} \frac{f(a+h)-f(a)}{h} exists as a single, finite number. Graphically, this means the curve has one well-defined, non-vertical tangent line at that point.

Three Ways Differentiability Fails

Corners: The graph approaches a point with different slopes from left and right. The classic example is f(x)=∣x∣f(x) = |x| at x=0x=0. From the right, f′(x)=1f'(x) = 1; from the left, f′(x)=−1f'(x) = -1. Since lim⁡h→0∣h∣h\lim_{h\to 0}\frac{|h|}{h} yields 11 for h>0h>0 and −1-1 for h<0h<0, the two-sided limit does not exist.

Graph illustrating Differentiability

Cusps: One-sided slopes blow up to opposite infinities from both sides, pinching the graph to a sharp point. For f(x)=x2/3f(x) = x^{2/3} at x=0x=0, the slope approaches +∞+\infty from the right and −∞-\infty from the left, so f′(0)f'(0) does not exist.

Graph illustrating Differentiability (2)

Vertical Tangents: The graph is smooth but the tangent line becomes vertical—the slope approaches the same infinity from both sides. For f(x)=x3f(x) = \sqrt[3]{x} at x=0x=0, we have f′(x)=13x−2/3f'(x) = \frac{1}{3}x^{-2/3}, so f′(0)=+∞f'(0) = +\infty from both sides. The limit is infinite, not finite, so the function is not differentiable.

Critical Insight

Differentiability implies continuity, but continuity does not imply differentiability. A function can be continuous everywhere yet fail to be differentiable at points with sharp features. Always check the limit definition when a graph looks sharp or vertical.

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