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Power rule with a large exponent

Let f(x)=x100f(x) = x^{100}. Find f′(x)f'(x).

Hint

Apply the power rule ddx[xn]=nxn−1\frac{d}{dx}[x^n] = n x^{n-1} with n=100n = 100: bring the exponent down as a multiplying coefficient, then subtract 1 from the exponent.

Step-by-step solution

The power rule states that for f(x)=xnf(x) = x^n, the derivative is f′(x)=nxn−1f'(x) = n x^{n-1}. Here n=100n = 100, so we multiply by 100 and reduce the exponent by 1.

This gives f′(x)=100x100−1=100x99f'(x) = 100 x^{100-1} = 100x^{99}.

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