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Limit at infinity and horizontal asymptote

Consider the function g(x)=5−2x2g(x) = 5 - \dfrac{2}{x^2}.

Evaluate lim⁡x→∞g(x)\displaystyle\lim_{x \to \infty} g(x) and lim⁡x→−∞g(x)\displaystyle\lim_{x \to -\infty} g(x). Based on these results, state the equation of the horizontal asymptote of g(x)g(x).

Hint

As x→±∞x \to \pm\infty, think about what happens to 2x2\dfrac{2}{x^2} — does it grow, shrink, or stay the same? Use this to determine what value g(x)g(x) approaches.

Step-by-step solution

As x→±∞x \to \pm\infty, the denominator x2x^2 grows without bound, so the fraction 2x2\dfrac{2}{x^2} approaches 00. This is true regardless of whether xx approaches +∞+\infty or −∞-\infty, since x2x^2 is always positive and grows large in either direction.

Therefore g(x)=5−2x2→5−0=5g(x) = 5 - \dfrac{2}{x^2} \to 5 - 0 = 5 as x→∞x \to \infty and as x→−∞x \to -\infty. Since both limits equal the finite value 55, the graph of g(x)g(x) has a horizontal asymptote at y=5y = 5.

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