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Limit at infinity and horizontal asymptote for f(x) = ln(x)/x

Consider the function f(x)=ln⁡(x)xf(x) = \dfrac{\ln(x)}{x}, defined for x>0x > 0.

Evaluate the limit lim⁡x→+∞ln⁡(x)x\lim_{x \to +\infty} \frac{\ln(x)}{x} and use your result to state the equation of the horizontal asymptote of f(x)=ln⁡(x)xf(x) = \dfrac{\ln(x)}{x} as x→+∞x \to +\infty (or state that there is none).

Hint

Recall that ln⁡(x)\ln(x) grows much more slowly than xx as x→∞x \to \infty. Think about which function 'wins' the race to infinity, or recall the general fact that logarithmic growth is dominated by any positive power of xx.

Step-by-step solution

As x→+∞x \to +\infty, both ln⁡(x)\ln(x) and xx grow without bound, so this is an ∞/∞\infty/\infty situation. However, ln⁡(x)\ln(x) grows much more slowly than xx: for large xx, the denominator outpaces the numerator by an ever-increasing factor. This is analogous to comparing a slowly growing power (like x1/10x^{1/10}) against x1x^1 in a rational-function comparison — the higher power in the denominator dominates.

Since xx grows faster than ln⁡(x)\ln(x) for all large xx, the ratio ln⁡(x)/x\ln(x)/x shrinks toward 00. Formally, lim⁡x→∞ln⁡xx=0\lim_{x\to\infty}\frac{\ln x}{x}=0. Because this finite limit exists as x→+∞x\to+\infty, the graph of ff approaches the horizontal line y=0y=0, so y=0y=0 is a horizontal asymptote.

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