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End behavior and horizontal asymptote of a rational function

Consider the rational function h(x)=7x+23x3−x2+1.h(x) = \dfrac{7x+2}{3x^3 - x^2 + 1}.

Find lim⁡x→∞h(x)\lim_{x \to \infty} h(x) and lim⁡x→−∞h(x)\lim_{x \to -\infty} h(x). Based on these limits, state the equation of the horizontal asymptote of h(x)h(x), if one exists.

Hint

Compare the degree of the numerator (degree 1) to the degree of the denominator (degree 3). When the denominator's degree is larger, dividing numerator and denominator by the highest power of xx in the denominator makes the fractional terms vanish as x→±∞x \to \pm\infty.

Step-by-step solution

Divide numerator and denominator by x3x^3, the highest power of xx appearing in the denominator: h(x)=7x+23x3−x2+1=7x2+2x33−1x+1x3.h(x) = \frac{7x+2}{3x^3-x^2+1} = \frac{\frac{7}{x^2} + \frac{2}{x^3}}{3 - \frac{1}{x} + \frac{1}{x^3}}. As x→±∞x \to \pm\infty, every term with xx in the denominator tends to 00.

This leaves 0+03−0+0=0\frac{0+0}{3-0+0} = 0, so lim⁡x→∞h(x)=0\lim_{x\to\infty} h(x) = 0 and lim⁡x→−∞h(x)=0\lim_{x\to -\infty} h(x) = 0. Since the degree of the numerator (1) is less than the degree of the denominator (3), this matches the general rule that such rational functions tend to 0 at both ends. Therefore the horizontal asymptote is y=0y = 0.

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