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End behavior and horizontal asymptote of a rational function

Consider the rational function h(x)=x3−8x3+8h(x) = \dfrac{x^3 - 8}{x^3 + 8}.

Find lim⁡x→∞h(x)\displaystyle\lim_{x \to \infty} h(x) and lim⁡x→−∞h(x)\displaystyle\lim_{x \to -\infty} h(x), and use these results to state the equation of the horizontal asymptote of h(x)h(x), if one exists.

Hint

Compare the degrees of the numerator and denominator. Since they are equal, divide every term by the highest power of xx present (here, x3x^3) and consider what happens to the terms with xx in the denominator as x→±∞x \to \pm\infty.

Step-by-step solution

Since the numerator and denominator are both degree 3 polynomials, divide every term by x3x^3: h(x)=x3−8x3+8=1−8x31+8x3.h(x) = \frac{x^3 - 8}{x^3 + 8} = \frac{1 - \frac{8}{x^3}}{1 + \frac{8}{x^3}}. As x→∞x \to \infty or x→−∞x \to -\infty, the terms 8x3→0\frac{8}{x^3} \to 0, so the expression approaches 1−01+0=1\frac{1 - 0}{1 + 0} = 1.

Since both one-sided limits at infinity equal the ratio of the leading coefficients (1/1=11/1 = 1), we get lim⁡x→∞h(x)=1,lim⁡x→−∞h(x)=1.\lim_{x\to\infty} h(x) = 1, \qquad \lim_{x\to -\infty} h(x) = 1. Because both limits are the same finite value, the function has a single horizontal asymptote at y=1y = 1.

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