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Estimating a two-sided limit from a graph with a hole

The graph below shows a function f(x)f(x) that is defined for all xx near −1-1, but is undefined at x=−1x = -1 itself (there is an open circle in the graph at that point).

Consider the function f(x)f(x) shown in the graph below. Notice that the curve has a small open circle at x=−1x = -1, indicating that f(−1)f(-1) is undefined, but the curve is smooth and unbroken everywhere else near x=−1x = -1.

Estimating a two-sided limit from a graph with a hole graph

Using the graph, what is lim⁡x→−1f(x)\displaystyle\lim_{x \to -1} f(x)?

Hint

Look at the height of the curve as xx gets closer and closer to −1-1 from both the left and the right side — ignore the open circle itself, since the limit only cares about nearby values, not the value at x=−1x=-1.

Step-by-step solution

As xx approaches −1-1 from the left, the curve rises smoothly and approaches a height of 44 on the vertical axis. Similarly, as xx approaches −1-1 from the right, the curve also approaches a height of 44. So both one-sided limits appear to equal 44.

Since the left-hand limit and the right-hand limit are both 44, the two-sided limit exists and equals 44. The fact that the graph has an open circle at x=−1x=-1 (meaning f(−1)f(-1) is undefined) has no effect on this conclusion, because the limit only depends on values of f(x)f(x) near x=−1x=-1, not at x=−1x=-1 itself.

Effect of the undefined point on the limit value

Does the open circle at x=−1x = -1 (indicating that f(−1)f(-1) is undefined) change what the limit lim⁡x→−1f(x)\displaystyle\lim_{x \to -1} f(x) actually equals?

Hint
Step-by-step solution

No, it does not change the limit at all. The limit only depends on the values of the function near x=−1x = -1, not on the value at x=−1x = -1 itself. Even though f(−1)f(-1) is undefined, the curve still approaches the height of four from both sides. So the limit is four regardless of the hole.

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