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Geometric Integrals

A geometric integral evaluates ∫abf(x) dx\int_a^b f(x)\,dx by recognizing the region between f(x)f(x) and the xx-axis as a familiar shape—triangle, rectangle, trapezoid, or circle—then applying its area formula with appropriate sign: positive above the axis, negative below.

Geometric Integrals: Finding Area Without Antiderivatives

The definite integral ∫abf(x) dx\int_a^b f(x)\,dx represents signed area between the curve f(x)f(x) and the xx-axis over [a,b][a,b]. Area above the axis counts positively; area below counts negatively. When the enclosed region is a recognizable geometric shape, you can find the integral directly using area formulas—no antiderivative needed.

How It Works

Sketch f(x)f(x) over [a,b][a,b] and identify the enclosed region's shape. Use the appropriate area formula, then attach the correct sign based on the region's position relative to the xx-axis. This method works because the definite integral is defined as a limit of Riemann sums approximating exactly this area.

Common Shapes and Formulas

ShapeFormula
RectangleA=base×heightA = \text{base} \times \text{height}
TriangleA=12base×heightA = \frac{1}{2}\text{base} \times \text{height}
TrapezoidA=12(b1+b2)hA = \frac{1}{2}(b_1+b_2)h
Circle/SemicircleA=πr2A = \pi r^2 or 12πr2\frac{1}{2}\pi r^2

Examples

Triangle: For ∫04x dx\int_0^4 x\,dx, the line y=xy=x forms a right triangle with base 4 and height 4 above the axis. Area: 12(4)(4)=8\frac{1}{2}(4)(4) = 8, so the integral equals 88.

Semicircle: For ∫−22−4−x2 dx\int_{-2}^{2} -\sqrt{4-x^2}\,dx, the curve is the lower half of a circle with radius 2, entirely below the axis. The semicircle's area is 12π(2)2=2π\frac{1}{2}\pi(2)^2 = 2\pi, but negative: ∫−22−4−x2 dx=−2π\int_{-2}^{2} -\sqrt{4-x^2}\,dx = -2\pi

Handling Mixed Regions

When f(x)f(x) crosses the xx-axis, split the integral at each zero and evaluate each piece with its own sign, then sum the results: ∫−34x dx=−12(3)(3)⏟below+12(4)(4)⏟above=3.5\int_{-3}^4 x\,dx = \underbrace{-\frac{1}{2}(3)(3)}_{\text{below}} + \underbrace{\frac{1}{2}(4)(4)}_{\text{above}} = 3.5

Key takeaway: Always determine the sign based on whether each region lies above or below the axis before finalizing your answer.

Practice problems

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