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Indefinite integral using u-substitution with u = tan(x)

Evaluate the indefinite integral ∫sec⁡2(x)tan⁡4(x) dx\int \sec^2(x)\tan^4(x)\,dx using the substitution u=tan⁡(x)u = \tan(x).

Hint

Let u=tan⁡(x)u = \tan(x). Then compute dudu in terms of sec⁡2(x) dx\sec^2(x)\,dx, and rewrite the entire integral in terms of uu only before integrating.

Step-by-step solution

Let u=tan⁡(x)u = \tan(x), so du=sec⁡2(x) dxdu = \sec^2(x)\,dx. Substituting into the integral, sec⁡2(x) dx\sec^2(x)\,dx becomes dudu and tan⁡4(x)\tan^4(x) becomes u4u^4, so the integral transforms into ∫u4 du\int u^4\,du.

Integrating with the power rule gives ∫u4 du=u55+C\int u^4\,du = \dfrac{u^5}{5} + C. Substituting back u=tan⁡(x)u = \tan(x) yields the final answer tan⁡5(x)5+C\dfrac{\tan^5(x)}{5} + C.

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