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Indefinite integral of e^(5x) via u-substitution

Evaluate the indefinite integral ∫e5x dx\int e^{5x}\,dx by using the substitution u=5xu = 5x.

Hint

Let u=5xu = 5x, so du=5 dxdu = 5\,dx, which means dx=15dudx = \frac{1}{5}du. Substitute these into the integral to rewrite it entirely in terms of uu, then integrate and substitute back for xx.

Step-by-step solution

Let u=5xu = 5x. Then du=5 dxdu = 5\,dx, so dx=15 dudx = \frac{1}{5}\,du. Substituting into the integral gives ∫e5x dx=∫eu⋅15 du=15∫eu du.\int e^{5x}\,dx = \int e^{u}\cdot \frac{1}{5}\,du = \frac{1}{5}\int e^{u}\,du.

The integral of eue^u is simply eue^u, so 15∫eu du=15eu+C\frac{1}{5}\int e^{u}\,du = \frac{1}{5}e^{u} + C. Substituting back u=5xu = 5x gives the final answer ∫e5x dx=15e5x+C.\int e^{5x}\,dx = \frac{1}{5}e^{5x} + C.

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