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Differentiating an accumulation function

Let F(x)=∫−2x(t4−2t) dt.F(x) = \int_{-2}^{x} (t^4 - 2t)\, dt. Find F′(x)F'(x).

Hint

Use the Fundamental Theorem of Calculus, Part 1: the derivative of an accumulation function with respect to its upper limit is just the integrand evaluated at that upper limit, provided the integrand is continuous.

Step-by-step solution

The Fundamental Theorem of Calculus, Part 1 states that if ff is continuous, then ddx∫axf(t) dt=f(x)\frac{d}{dx}\int_a^x f(t)\,dt = f(x). Here the integrand is f(t)=t4−2tf(t) = t^4 - 2t, which is a polynomial and therefore continuous everywhere, so the theorem applies directly with a=−2a = -2.

Since the upper limit of integration is simply xx (not a function of xx), no chain rule is needed. We just replace tt with xx in the integrand to get F′(x)=x4−2xF'(x) = x^4 - 2x.

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