General antiderivative of sec^2(x) - 5

Since antidifferentiation is linear, we can find the antiderivative of each term separately: $\int \sec^2(x)\, dx$ and $\int -5\, dx$.

Using the known rule $\int \sec^2 x\, dx = \tan x + C$ and $\int -5\, dx = -5x + C$, combine these results and add a single arbitrary constant $C$ to get $G(x) = \tan(x) - 5x + C$.