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Derivative of a constant involving pi

Let f(x)=π2f(x) = \pi^2. Find f′(x)f'(x).

Hint

Remember that π\pi is just a fixed number, so π2\pi^2 is a constant, not a variable expression. What is the derivative of any constant?

Step-by-step solution

Even though it involves the symbol π\pi, the quantity π2\pi^2 is a fixed real number (approximately 9.879.87), not a function of xx. There is no xx anywhere in the expression, so f(x)f(x) does not change as xx changes.

By the constant rule, ddx[c]=0\frac{d}{dx}[c] = 0 for any constant cc. Applying this with c=π2c = \pi^2 gives f′(x)=0f'(x) = 0.

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