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Behavior near a vertical asymptote

Consider the function f(x)=cos⁡(x)x2f(x) = \dfrac{\cos(x)}{x^2}.

Evaluate the limit lim⁡x→0cos⁡(x)x2\lim_{x \to 0} \frac{\cos(x)}{x^2} using infinity notation to describe the behavior of f(x)f(x) near x=0x=0, and state whether x=0x=0 is a vertical asymptote of ff.

Hint

Look separately at the numerator and denominator as x→0x \to 0: what value does cos⁡(x)\cos(x) approach, and what happens to x2x^2? Since x2>0x^2 > 0 on both sides of 00, check whether the one-sided limits agree.

Step-by-step solution

As x→0x \to 0, the numerator cos⁡(x)→cos⁡(0)=1\cos(x) \to \cos(0) = 1, a positive constant. The denominator x2→0+x^2 \to 0^+ from both the left and the right, since squaring makes it positive regardless of the sign of xx.

A positive constant divided by a quantity approaching 0+0^+ grows without bound, so both one-sided limits equal +∞+\infty: lim⁡x→0−cos⁡xx2=+∞,lim⁡x→0+cos⁡xx2=+∞.\lim_{x\to 0^-}\frac{\cos x}{x^2} = +\infty, \quad \lim_{x\to 0^+}\frac{\cos x}{x^2} = +\infty. Therefore lim⁡x→0cos⁡xx2=+∞\lim_{x\to 0} \frac{\cos x}{x^2} = +\infty, and since ff is undefined at x=0x=0 with an infinite one-sided limit there, x=0x=0 is a vertical asymptote.

Sign of the infinite limit at the asymptote

Hint
Step-by-step solution

The function grows toward positive infinity. Since cosine of zero equals one, a positive value, and x squared approaches zero from the positive side on both sides of zero, the quotient becomes a large positive number. Both one-sided limits were found to equal positive infinity, so the function increases without bound near x equals zero rather than decreasing.

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