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Using linearity to evaluate a combined integral

Suppose ∫15f(x) dx=8\int_1^5 f(x)\,dx = 8 and ∫15g(x) dx=3\int_1^5 g(x)\,dx = 3.

Use the given information and linearity of the definite integral to evaluate ∫15[4f(x)−2g(x)]dx.\int_1^5 \left[4f(x) - 2g(x)\right]dx.

Hint

Split the integral of the sum/difference into separate integrals, then pull the constant factors out front using linearity: ∫15[4f(x)−2g(x)]dx=4∫15f(x)dx−2∫15g(x)dx\int_1^5[4f(x)-2g(x)]dx = 4\int_1^5 f(x)dx - 2\int_1^5 g(x)dx.

Step-by-step solution

By linearity of the definite integral, the integral of a difference is the difference of the integrals, and constant multiples can be factored out: ∫15[4f(x)−2g(x)]dx=4∫15f(x) dx−2∫15g(x) dx.\int_1^5 \left[4f(x) - 2g(x)\right]dx = 4\int_1^5 f(x)\,dx - 2\int_1^5 g(x)\,dx.

Substituting the given values ∫15f(x)dx=8\int_1^5 f(x)dx = 8 and ∫15g(x)dx=3\int_1^5 g(x)dx = 3 gives 4(8)−2(3)=32−6=264(8) - 2(3) = 32 - 6 = 26. So the value of the integral is 2626.

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