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Net change in accumulated stress via the Net Change Theorem

Engineers model the rate of structural stress accumulation in a beam as F′(x)=sec⁡2(x)F'(x) = \sec^2(x), where xx is measured in radians corresponding to a load parameter, and F(x)F(x) is the accumulated stress.

The rate of structural stress accumulation is given by F′(x)=sec⁡2(x)F'(x) = \sec^2(x). Use the Net Change Theorem to find the total change in stress, F(π4)−F(0)F\left(\frac{\pi}{4}\right) - F(0), as xx varies from 00 to π4\frac{\pi}{4}.

Hint

The Net Change Theorem says ∫abF′(x) dx=F(b)−F(a)\int_a^b F'(x)\,dx = F(b) - F(a). Recall that the antiderivative of sec⁡2(x)\sec^2(x) is tan⁡(x)\tan(x), then evaluate at the two bounds.

Step-by-step solution

By the Net Change Theorem, the total change equals ∫0π/4sec⁡2(x) dx\int_0^{\pi/4} \sec^2(x)\,dx. This directly represents the accumulated change in FF over the interval, since F′(x)=sec⁡2(x)F'(x) = \sec^2(x) is the rate of change.

An antiderivative of sec⁡2(x)\sec^2(x) is tan⁡(x)\tan(x), so ∫0π/4sec⁡2(x) dx=tan⁡(π4)−tan⁡(0)=1−0=1\int_0^{\pi/4} \sec^2(x)\,dx = \tan\left(\frac{\pi}{4}\right) - \tan(0) = 1 - 0 = 1. Thus the total change in accumulated stress from x=0x=0 to x=π/4x=\pi/4 is 11.

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