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Evaluate a definite integral of an exponential function using FTC Part 2

Evaluate the definite integral: ∫0ln⁡2ex dx\int_0^{\ln 2} e^x \, dx

Hint

Find an antiderivative F(x)F(x) of exe^x, then compute F(ln⁡2)−F(0)F(\ln 2) - F(0) using the Fundamental Theorem of Calculus, Part 2. Recall that eln⁡2=2e^{\ln 2} = 2.

Step-by-step solution

An antiderivative of f(x)=exf(x) = e^x is F(x)=exF(x) = e^x, since ddx[ex]=ex\frac{d}{dx}[e^x] = e^x. By the Fundamental Theorem of Calculus, Part 2, ∫0ln⁡2ex dx=F(ln⁡2)−F(0)=ex∣0ln⁡2\int_0^{\ln 2} e^x\,dx = F(\ln 2) - F(0) = e^x\Big|_0^{\ln 2}.

Substituting the limits gives eln⁡2−e0e^{\ln 2} - e^0. Since eln⁡2=2e^{\ln 2} = 2 and e0=1e^0 = 1, the value of the integral is 2−1=12 - 1 = 1.

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