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Simplify and find the general antiderivative of a rational function

Let h(x)=x3+2xxh(x) = \dfrac{x^3 + 2x}{x}.

First simplify h(x)h(x) into a polynomial with no fractions, and then find the general antiderivative H(x)H(x) such that H′(x)=h(x)H'(x) = h(x).

What is H(x)H(x)?

Hint

Divide each term in the numerator by xx first to rewrite h(x)h(x) as a simple polynomial, then apply the power rule to each term. Don't forget the constant of integration.

Step-by-step solution

Split the fraction term by term: h(x)=x3x+2xx=x2+2h(x) = \dfrac{x^3}{x} + \dfrac{2x}{x} = x^2 + 2, valid for x≠0x \neq 0. This removes the fraction and leaves a simple polynomial to integrate.

Apply the power rule to each term: ∫x2 dx=x33\int x^2\,dx = \dfrac{x^3}{3} and ∫2 dx=2x\int 2\,dx = 2x. Adding the arbitrary constant of integration gives the general antiderivative H(x)=x33+2x+CH(x) = \dfrac{x^3}{3} + 2x + C.

Why the constant term is missing from the original fraction

Hint
Step-by-step solution

Because differentiation kills constants, any constant added to the simplified function x squared plus two vanishes when you take a derivative. So when reversing the process to find the antiderivative, infinitely many constants are equally valid. Writing plus C accounts for every possible constant that could have been present originally. This is why the plus C is required, not optional.

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