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General antiderivative of a polynomial-exponential-reciprocal function

Find the general antiderivative of f(x)=10x4−ex+1x.f(x) = 10x^4 - e^x + \frac{1}{x}.

Hint

Apply the antiderivative rules to each term separately: reverse the power rule for 10x410x^4, recall that exe^x is its own antiderivative, and remember that ∫1x dx=ln⁡∣x∣\int \frac{1}{x}\,dx = \ln|x|. Don't forget the constant of integration at the end.

Step-by-step solution

Integrate term by term using linearity. For 10x410x^4, use the power rule: ∫10x4 dx=10⋅x55=2x5\int 10x^4\,dx = 10\cdot \frac{x^5}{5} = 2x^5. For −ex-e^x, recall ∫ex dx=ex\int e^x\,dx = e^x, so this term contributes −ex-e^x. For 1x\frac{1}{x}, recall ∫1x dx=ln⁡∣x∣\int \frac{1}{x}\,dx = \ln|x|.

Combining these results gives 2x5−ex+ln⁡∣x∣2x^5 - e^x + \ln|x|. Since the derivative of any constant is zero, we must add an arbitrary constant CC to represent the entire family of antiderivatives. The final general antiderivative is F(x)=2x5−ex+ln⁡∣x∣+CF(x) = 2x^5 - e^x + \ln|x| + C.

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