Intervals of increase/decrease and classification of local extrema
Consider the function on the interval .
Find the critical numbers of in , determine the intervals on which is increasing and decreasing, and use the First Derivative Test to classify each critical point as a local maximum, local minimum, or neither.
Hint
Compute , use the double angle identity to rewrite as a quadratic in , factor to find where on , then check the sign of on each subinterval.
Step-by-step solution
First compute . Using , rewrite this as . Setting gives or . On this yields as critical points.
Testing sample points in each subinterval: on pick : (increasing). On pick : (decreasing). On pick : (decreasing). On pick : (increasing).
To find the local extrema values: at , . At , . Since changes from positive to negative at , this is a local maximum. Since changes from negative to positive at , this is a local minimum. At , but remains negative on both and , so does not change sign at this critical point, making it neither a local maximum nor minimum.
Behavior at the critical point where the derivative fails to change sign
Hint
Step-by-step solution
At x = π, the derivative equals zero since cos(π) = -1 makes the factor (cos(x) + 1) equal zero. However, the derivative does not change sign at this point. Since r'(x) = 2(2cos(x) - 1)(cos(x) + 1) is negative immediately before π (where cos(x) > -1) and remains negative immediately after π (where cos(x) > -1), the First Derivative Test cannot classify this as a local extremum. The function is decreasing through x = π with no turning behavior. Therefore this critical point is neither a local maximum nor a local minimum.
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